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- Thread starter mary1900
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exp(A) B exp(A)= B + {A,B} + {A,{A,B}} +.....

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strangerep

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If A and B are anti-commuting quantities, then I presume you also mean ##A^2=0 =B^2## ?

If so, then ##\exp(A) = 1 + A## (since higher order powers vanish). That simplifies all formulas considerably...

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